70-059TCP/IP 4.0 试题回顾（7）(1) |
| 论文作者：佚名 论文来源：不详 论文发布时间：2006-6-9 2:23:54 论文发布人：chjchjchj |
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person one ：
How I did it and what percentage each played in the success of the exam:
Transcender: 50%
Exam Cram: 15%
NT Resource: 5%
Brain Dumps: 25%
Hands on: 5%
I charted out the subnet matrix (only class C hosts) and then when I got a question concerning a Class B address I calculated the B hosts real quick with the calculator (took 30 seconds and I was way ahead on time)
Lots of folks make this step a lot more complicated than it is. If you can remember 192 - 2 - 62 everything else is a mathematical progression from there. To get the amount of B Hosts just take the number of C Hosts (not VALID C hosts, all C Hosts, ie. 64 not 62) and multiple by 256 and subtract 2. To get number of A hosts take C hosts and multiply it by 256 and 256 again and subtract 2. Simple huh?
Now there were no questions with regard to A class hosts so don t bother with that.
Also as everyone has said, no switch questions for any utilities. Another thing to note, if you are stuck on not being able to figure out the tough stuff like ANDing and figuring out whether two addresses are on the same segment etc.&n
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